If 0.15 g of a solute, dissolved in 15 g of solvent, is boiled at a temperature higher by 0.216 ℃ than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is 2.16 ℃ ) is

Question

If 0.15 g of a solute, dissolved in 15 g of solvent, is boiled at a temperature higher by 0.216 ℃ than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is 2.16 ℃ ) is, 100, 80, 10, 1.001

MARKS App · Accepted Answer

weight of solute (w) =0.15 g, weight of solvent (W)=15 g, ∆ T b =0.216 ℃ k b = 2.16 ℃ ∴ M= k b × w × 1000 ∆ T b × W = 2.16 × 0.15 × 1000 0.216 × 15 = 100

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