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If $0.189 \mathrm{~g}$ of a chlorine containing organic compound gave $0.287 \mathrm{~g}$ of silver chloride, then the percentage of chlorine in the organic compound is
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Verified Answer
The correct answer is:
37.57
Organic compound $\rightarrow$ Comp. $+\mathrm{AgCl}$ $0.189 \mathrm{~g} \quad 0.287 \mathrm{~g}$
Percentage of chlorine in $\mathrm{AgCl}=\frac{35.5}{143.35} \times 100$ $=24.76 \%$
Weight of chlorine in $0.287 \mathrm{~g}$
$$
\begin{aligned}
\mathrm{g} \mathrm{AgCl} & =\frac{24.76}{100} \times 0.287 \\
& =.07106 \mathrm{~g}
\end{aligned}
$$
Percentage of chlorine in 0.189
$$
\begin{aligned}
\mathrm{g} & =\frac{.07106}{0.189} \times 100 \\
& =37.598 \%
\end{aligned}
$$
Percentage of chlorine in $\mathrm{AgCl}=\frac{35.5}{143.35} \times 100$ $=24.76 \%$
Weight of chlorine in $0.287 \mathrm{~g}$
$$
\begin{aligned}
\mathrm{g} \mathrm{AgCl} & =\frac{24.76}{100} \times 0.287 \\
& =.07106 \mathrm{~g}
\end{aligned}
$$
Percentage of chlorine in 0.189
$$
\begin{aligned}
\mathrm{g} & =\frac{.07106}{0.189} \times 100 \\
& =37.598 \%
\end{aligned}
$$
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