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If $1^{\circ}=\alpha$ radians, then the approximate value of $\cos \left(60^{\circ} 1^{\prime}\right)$ is
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$\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}$
$\therefore \cos \left(60^{\circ} 1^{\prime}\right)=\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}$
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