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Question: Answered & Verified by Expert
If 1+x+2x220=a0+a1x+a2x2+....+a40x40, then the value of a0+a2+a4+.....+a38 is
MathematicsBinomial TheoremJEE Main
Options:
  • A 220220-1
  • B 220220+1
  • C 239-219
  • D 239+219
Solution:
2496 Upvotes Verified Answer
The correct answer is: 239-219
In the given identity, substituting x=1 and x=-1 on both the sides and adding, we get, 
2a0+a2+a4+.....+a40=420+220
=240+220
a0+a2+a4+....+a38+a40=239+219
But, a40 is the coefficient of x40 which is 220.
Therefore, a0+a2+a4+.....+a38+220=239+219
a0+a2+a4+.....+a38=239+219-2.219=239-219

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