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Question: Answered & Verified by Expert
If 1+xn=C0+C1x+C2x2+....+Cnxn, r=0nr+12 Cr=2n-2fn and if the roots of the equation fx=0 are α and β, then the value of α2+β2 is equal to (where Cr denotes Crn)
MathematicsBinomial TheoremJEE Main
Options:
  • A 13
  • B 10
  • C 17
  • D 20
Solution:
1349 Upvotes Verified Answer
The correct answer is: 17
1+xn=r=0nCrxr
x1+xn=r=0nCrxr+1
Differentiating w.r.t. x we get
xn1+xn-1+1+xn=r=0nr+1Crxr
Again multiplying both sides by x
1+xn-1nx+1+xx=r=0nr+1Crxr+1
Again differentiating w.r.t. x we get,
ddx1+xn-1nx2+x2+x=r=0nr+12Crxr
r=0nr+12Crxr=1+xn-12nx+2x+1+nx2+x2+xn-11+xn-2
Putting x=1 on both sides, we get,
r=0nr+12Cr=2n-12n+3+n+2n-12n-2=2n-2n2+5n+4
Now, fx=x2+5x+4=x+1x+4α=-1, β=-4
Hence, α2+β2=17

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