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If $\left(1+x+x^2\right)^n=a_0+a_1 x+a_2 x^2+\ldots+a_{2 n} x^{2 n}$, then $a_0+a_2+a_4+\ldots+a_{2 n}=$
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The correct answer is:
$\frac{3^n+1}{2}$
No solution. Refer to answer key.
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