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If 1.0 mole of $I_{2}$ is introduced into 1.0 litre flask at $1000 \mathrm{~K},$ at equilibrium $\left(\mathrm{K}_{\mathrm{c}}=10^{-6}\right),$ which one is correct?
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Verified Answer
The correct answer is:
$\left[\mathrm{I}_{2}(\mathrm{~g})\right]<\left[\mathrm{I}^{-}(\mathrm{g})\right]$

$K_{C}=\frac{(2 x)^{2}}{(1-x)}=10^{-6}$
It shows that $(1-x)<2 x$
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