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Question: Answered & Verified by Expert
If 1.0 mole of $I_{2}$ is introduced into 1.0 litre flask at $1000 \mathrm{~K},$ at equilibrium $\left(\mathrm{K}_{\mathrm{c}}=10^{-6}\right),$ which one is correct?
ChemistryChemical EquilibriumJEE Main
Options:
  • A $\left[\mathrm{I}_{2}(\mathrm{~g})\right]>\left[\mathrm{I}^{-}(\mathrm{g})\right]$
  • B $\left[\mathrm{I}_{2}(\mathrm{~g})\right]<\left[\mathrm{I}^{-}(\mathrm{g})\right]$
  • C $\left[\mathrm{I}_{2}(\mathrm{~g})\right]=\left[\mathrm{I}^{-}(\mathrm{g})\right]$
  • D $\left[\mathrm{I}_{2}(\mathrm{~g})\right]=\frac{1}{2}\left[\mathrm{I}^{-}(\mathrm{g})\right]$
Solution:
2617 Upvotes Verified Answer
The correct answer is: $\left[\mathrm{I}_{2}(\mathrm{~g})\right]<\left[\mathrm{I}^{-}(\mathrm{g})\right]$



$K_{C}=\frac{(2 x)^{2}}{(1-x)}=10^{-6}$

It shows that $(1-x)<2 x$

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