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Question: Answered & Verified by Expert
If 10% of the power of a 100π W light bulb is converted to visible radiation, then the average intensity of visible radiation at a distance of 10 m is
PhysicsElectromagnetic WavesJEE Main
Options:
  • A 0.025 W m-2
  • B 0.01 W m-2
  • C 0.031 W m-2
  • D 0.05 W m-2
Solution:
1572 Upvotes Verified Answer
The correct answer is: 0.025 W m-2

The intensity is defined as power radiated per unit area here power, P=100π W, but in the question we want to calculate only for ten percent of origin it means, P'=10π W, so the intensity, 
I=P'4πd2=10π4π102=0.025 W m-2

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