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If $100$ times the $100^{\text {th }}$ term of an $AP$ with non zero common difference equals the $50$ times its $50^{\text {th }}$ term, then the $150^{\text {th }}$ term of this $A P$ is
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zero
zero
$100\left(T_{100}\right)=50\left(T_{50}\right) \quad \Rightarrow 2[a+99 d]=a+49 d \Rightarrow a+149 d=0 \quad \Rightarrow T_{150}=0$
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