If θ = π 12 and x = log cot π 4 + θ , then cosh x =

Question

If θ = π 12 and x = log cot π 4 + θ , then cosh x =, 2 3, - 2 3, 3 2, - 3 2

MARKS App · Accepted Answer

Given: x = log cot π 4 + θ ⇒ x = log cot π 4 + π 12 ⇒ x = log cot π 3 ⇒ x = log 1 3 ⇒ e x = 1 3 and e - x = 3 Now, cos h x = e x + e - x 2 ⇒ cos h x = 1 3 + 3 2 ⇒ cos h x = 2 3

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