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If $1.2 \mathrm{~g}$ of metal displace 1.12 litre hydrogen at normal temperature and pressure ,equivalent weight of metal would be
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$24$
1.12ltr $\mathrm{H}_2 1.2 \mathrm{~g} ;, 22.4$ ltr $\mathrm{H}_2=24 \mathrm{~g}$.
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