If 13 . 6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from its first excited state is

Question

If 13 . 6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from its first excited state is, 10 . 2 eV, 5.1 eV, 3.4 eV, 6.8 eV

MARKS App · Accepted Answer

The energy of an electron in hydrogen atom is E = - 13 . 6 n 2 eV So, the energy required to remove an electron from n = 2 state is E = 13 . 6 2 2 eV = 13 . 6 4 = 3 . 4 eV

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