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Question: Answered & Verified by Expert
If 13.6 eV energy is required to lionize the hydrogen atom, then the energy required to remove an electron from n=2 is :
PhysicsAtomic PhysicsNEET
Options:
  • A 10.2 eV
     
  • B 0 eV
     
     
  • C 3.4 eV
     
  • D 6.8 eV
     
Solution:
1559 Upvotes Verified Answer
The correct answer is: 3.4 eV
 

The energy required to remove an electron from nth orbit is n

En=-13.6n2

Here n=2

Therefore E2=-13.622
= -3.4 eV

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