If θ = 17 π 3 , then tan ⁡ θ

i f θ = 17 π 3 let A = t a n θ - c o t θ = - 2 1 - t a n 2 θ 2 t a n θ = - 2 t a n 2 θ = - 2 t a n 4 π 3 = - 2 tan ⁡ π 3 = - 2 3

Question: Answered & Verified by Expert

θ = \frac{17 π}{3},

then

(\tan θ - \cot θ)

________

MathematicsTrigonometric Ratios & IdentitiesMHT CETMHT CET 2019 (02 May Shift 1)

Options:

Solution:

2398 Upvotes Verified Answer

The correct answer is:

- \frac{2}{\sqrt{3}}

i f θ = \frac{17 π}{3}

let

A = (t a n θ - c o t θ)

= - 2 (\frac{1 - {t a n}^{2} θ}{2 t a n θ})

= \frac{- 2}{t a n 2 θ} = \frac{- 2}{t a n \frac{4 π}{3}}

= \frac{- 2}{\tan (\frac{π}{3})} = \frac{- 2}{\sqrt{3}}

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