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If $\left|\begin{array}{ccc}2 & 4 & 0 \\ 0 & 5 & 16 \\ 0 & 0 & 1+p\end{array}\right|=20$, then what is the value of $p$?
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The correct answer is:
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$\left|\begin{array}{ccc}2 & 4 & 0 \\ 0 & 5 & 16 \\ 0 & 0 & 1+p\end{array}\right|=20$
On expanding along $\mathrm{C}_{1}$, $2\{5(1+p)-0\}=20$
$\Rightarrow 1+p=2$
$\Rightarrow p=1$
On expanding along $\mathrm{C}_{1}$, $2\{5(1+p)-0\}=20$
$\Rightarrow 1+p=2$
$\Rightarrow p=1$
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