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If $(2,0)$ is the vertex and the $y$ -axis is the directrix of a parabola, then where is its focus?
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The correct answer is:
$(4,0)$
Vertec is $(2,0)$. Since, $y$ -axis is the directrix of a parabola. Equation directrix is $x=0 .$ So, axis of parabolais $x$ -axis. Let the focus be $(\mathrm{a}, 0)$

Distance of the vertex of a parabola from directrix = its distance from focus
So, $\mathrm{OV}=\mathrm{VF} \Rightarrow(2-0)^{2}=(\mathrm{a}-2)^{2}$
$a^{2}=4 a b a=4$
$\Rightarrow$ Focus is $(4,0)$

Distance of the vertex of a parabola from directrix = its distance from focus
So, $\mathrm{OV}=\mathrm{VF} \Rightarrow(2-0)^{2}=(\mathrm{a}-2)^{2}$
$a^{2}=4 a b a=4$
$\Rightarrow$ Focus is $(4,0)$
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