Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If $\left(2+\frac{x}{3}\right)^{55}$ is expanded in the ascending powers of $x$ and the coefficients of powers of $x$ in two consecutive terms of the expansion are equal, then these terms are:
MathematicsBinomial TheoremJEE MainJEE Main 2014 (12 Apr Online)
Options:
  • A
    $7^{\text {th }}$ and $8^{\text {th }}$
  • B
    $8^{\text {th }}$ and $9^{\text {th }}$
  • C
    $28^{\text {th }}$ and $29^{\text {th }}$
  • D
    $27^{\text {th }}$ and $28^{\text {th }}$
Solution:
1734 Upvotes Verified Answer
The correct answer is:
$7^{\text {th }}$ and $8^{\text {th }}$
Let $r^{\text {th }}$ and $(r+1)^{\text {th }}$ term has equal coefficient
$$
\begin{aligned}
&\left(2+\frac{x}{3}\right)^{55}=2^{55}\left(1+\frac{x}{6}\right)^{55} \\
&r^{\text {th }} \text { term }=2^{5555} C_r\left(\frac{x}{6}\right)^r
\end{aligned}
$$
Coefficient of $x^r$ is $2^{55}{ }^{55} C_r \frac{1}{6^r}$
$$
(r+1)^{\text {th }} \text { term }=2^{5555} C_{r+1}\left(\frac{x}{6}\right)^{r+1}
$$
Coefficient of $x^{r+1}$ is $2^{55}{ }^{55} C_{r+1} \cdot \frac{1}{6^{r+1}}$
Both coefficients are equal
$$
2^{5555} C_r \frac{1}{6^r}=2^{5555} C_{r+1} \frac{1}{6^{r+1}}
$$

$$
\begin{aligned}
&\frac{1}{|r| 55-r}=\frac{1}{\lfloor r+1 \mid 54-r} \cdot \frac{1}{6} \\
&6(r+1)=55-r \\
&6 r+6=55-r \\
&7 r=49 \\
&r=7 \\
&(r+1)=8
\end{aligned}
$$
Coefficient of $7^{\text {th }}$ and $8^{\text {th }}$ terms are equal.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.