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If $\left[\begin{array}{cc}2 & -3 \\ 4 & 0\end{array}\right]-\left[\begin{array}{ll}a & c \\ b & d\end{array}\right]=\left[\begin{array}{cc}1 & 4 \\ 2 & -5\end{array}\right]$, then $(a, b, c, d)=$
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The correct answer is:
$(1,2,-7,5)$
$\left[\begin{array}{cc}2 & -3 \\ 4 & 0\end{array}\right]-\left[\begin{array}{ll}a & c \\ b & d\end{array}\right]$$=\left[\begin{array}{cc}1 & 4 \\ 2 & -5\end{array}\right]$
$\Rightarrow\left[\begin{array}{ll}a & c \\ b & d\end{array}\right]$$=\left[\begin{array}{cc}2 & -3 \\ 4 & 0\end{array}\right]-\left[\begin{array}{cc}1 & 4 \\ 2 & -5\end{array}\right]=\left[\begin{array}{cc}1 & -7 \\ 2 & 5\end{array}\right]$
$\Rightarrow(a, b, c, d)=(1,2,-7,5)$.
$\Rightarrow\left[\begin{array}{ll}a & c \\ b & d\end{array}\right]$$=\left[\begin{array}{cc}2 & -3 \\ 4 & 0\end{array}\right]-\left[\begin{array}{cc}1 & 4 \\ 2 & -5\end{array}\right]=\left[\begin{array}{cc}1 & -7 \\ 2 & 5\end{array}\right]$
$\Rightarrow(a, b, c, d)=(1,2,-7,5)$.
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