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Question: Answered & Verified by Expert
If 2+cosx3+ydydx+sinx=0 and y0=1, then yπ3 is equal to
MathematicsDifferential EquationsJEE Main
Options:
  • A 43
  • B 73
  • C 13
  • D 1
Solution:
1488 Upvotes Verified Answer
The correct answer is: 13
dyy+3=-sinx2+cosxdx
lny+3=ln2+cosx+lnC
y+3=C(2+cosx)
Now, at x=0, y=1
4=3CC=43
y=432+cosx-3
Hence, yπ3=432+123=2353=13

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