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If 2 is the length of a side of a triangle with its opposite angle ' $\pi / 3$ ', then the circumradius of the triangle is ......
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Verified Answer
The correct answer is:
$\frac{2}{\sqrt{3}}$
According to the question,

$$
\because \quad a=2 \text { and } \angle A=\frac{\pi}{3}
$$
So, by sine Iaw, we have
$$
\frac{a}{\sin A}=2 R \Rightarrow \frac{2}{\sqrt{3} / 2}=2 R \Rightarrow R=\frac{2}{\sqrt{3}}
$$

$$
\because \quad a=2 \text { and } \angle A=\frac{\pi}{3}
$$
So, by sine Iaw, we have
$$
\frac{a}{\sin A}=2 R \Rightarrow \frac{2}{\sqrt{3} / 2}=2 R \Rightarrow R=\frac{2}{\sqrt{3}}
$$
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