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Question: Answered & Verified by Expert
If 2+xxx2x2+xx2x2x2+x=16x-ax-bx-cx-d be an identity in x where a,b,c,d are independent of x, then the value of 1325abcd is
MathematicsDeterminantsJEE Main
Solution:
1559 Upvotes Verified Answer
The correct answer is: 24.96
Since, the given equation is an identity in x, putting x=0, we get, 
200020002=16abcd
abcd=481325abcd=13×4825=24.96

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