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If $20 \mathrm{~cm}^3$ gas at $1 \mathrm{~atm}$. is expanded to $50 \mathrm{~cm}^3$ at constant $T$, then what is the final pressure
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The correct answer is:
$20 \times \frac{1}{50}$
At constant $T, P_1 V_1=P_2 V_2$
$1 \times 20=P_2 \times 50 ; \quad P_2=\frac{20}{50} \times 1$
$1 \times 20=P_2 \times 50 ; \quad P_2=\frac{20}{50} \times 1$
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