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If 3 sisters and 8 other girls are together playing a game, then the number of ways in which all the girls are seated around a circle such that the three sisters are not seated together, is
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Verified Answer
The correct answer is:
$8 ! \times 84$
The total number of ways that all girls seated around a circle is 10 !.
The number of ways the three sisters seated together along with the other girls is $8 ! \times 3$ !.
So, required number of ways $= 10 !-8 ! 3 !$
$=8 !(10 \times 9-6)$
$=8 ! \times 84$
The number of ways the three sisters seated together along with the other girls is $8 ! \times 3$ !.
So, required number of ways $= 10 !-8 ! 3 !$
$=8 !(10 \times 9-6)$
$=8 ! \times 84$
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