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If $3 x \equiv 5(\bmod 7)$, then
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Verified Answer
The correct answer is:
$x \equiv 4(\bmod 7)$
Given, $3 x \equiv 5(\bmod 7)$
$$
\begin{array}{cc}
\Rightarrow & 3 x-5=0(\bmod 7)=\frac{7}{3 x-5} \\
\Rightarrow & 3 x-5=7 P, \text { where } P \in Z \\
\Rightarrow & x \equiv 4(\bmod 7)
\end{array}
$$
$$
\begin{array}{cc}
\Rightarrow & 3 x-5=0(\bmod 7)=\frac{7}{3 x-5} \\
\Rightarrow & 3 x-5=7 P, \text { where } P \in Z \\
\Rightarrow & x \equiv 4(\bmod 7)
\end{array}
$$
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