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If $38 \cdot 55 \mathrm{~kJ}$ of heat is absorbed when $6 \cdot 0 \mathrm{~g}$ of $\mathrm{O}_{2}$ react with CIF according to reaction $2 \mathrm{CIF}_{(\mathrm{g})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{Cl}_{2} \mathrm{O}_{(\mathrm{g})}+0 \mathrm{~F}_{2}(\mathrm{~g})$
What is the standard enthalpy of reaction?
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What is the standard enthalpy of reaction?
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2287 Upvotes
Verified Answer
The correct answer is:
$205.6 \mathrm{k} \mathrm{J}$
(A)
$\begin{array}{l}
2 \mathrm{ClF}_{(\mathrm{g})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{Cl}_{2} \mathrm{O}_{(\mathrm{g})}+\mathrm{OF}_{2(\mathrm{~g})} \\
\text { For } 6.0 \mathrm{~g} \text { of } \mathrm{O}_{2} \Rightarrow \Delta \mathrm{H}=+38.55 \mathrm{~kJ} \\
\therefore \text { For } 32.0 \mathrm{~g} \text { of } \mathrm{O}_{2} \Rightarrow \Delta \mathrm{H}^{0}=\frac{38.55 \times 32}{6}=205.6 \mathrm{~kJ}
\end{array}$
$\begin{array}{l}
2 \mathrm{ClF}_{(\mathrm{g})}+\mathrm{O}_{2(\mathrm{~g})} \longrightarrow \mathrm{Cl}_{2} \mathrm{O}_{(\mathrm{g})}+\mathrm{OF}_{2(\mathrm{~g})} \\
\text { For } 6.0 \mathrm{~g} \text { of } \mathrm{O}_{2} \Rightarrow \Delta \mathrm{H}=+38.55 \mathrm{~kJ} \\
\therefore \text { For } 32.0 \mathrm{~g} \text { of } \mathrm{O}_{2} \Rightarrow \Delta \mathrm{H}^{0}=\frac{38.55 \times 32}{6}=205.6 \mathrm{~kJ}
\end{array}$
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