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If $\frac{1}{4}, \mathrm{a}, \mathrm{b}, \frac{1}{19}$ form a H.P. then the values of a and $\mathrm{b}$ are respectively
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The correct answer is:
$\frac{1}{9}, \frac{1}{14}$
$\frac{1}{4}, a, b, \frac{1}{19} \longrightarrow$ H.P.
$4, \frac{1}{a}, \frac{1}{b}, 19 \rightarrow$ AP
$a=\frac{1}{9}, b=\frac{1}{14}$
$4, \frac{1}{a}, \frac{1}{b}, 19 \rightarrow$ AP
$a=\frac{1}{9}, b=\frac{1}{14}$
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