If 4 3 + 8 3 + 1 2 3 + … up to n terms = k n 2 ( n + 1 ) 2 (for all n ∈ N ), then k =, 4, 8, 16, 32

If 4 3 + 8 3 + 1 2 3 + … up to n terms = k n 2 ( n + 1 ) 2 (for all n ∈ N ), then k =

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If $4^3+8^3+12^3+\ldots$ up to $n$ terms $=k n^2(n+1)^2$ (for all $n \in \mathrm{N}$), then $k=$

MathematicsSequences and SeriesAP EAMCETAP EAMCET 2017 (24 Apr Shift 1)

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Solution:

1228 Upvotes Verified Answer

The correct answer is: 16

No solution. Refer to answer key.

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