If 5 mg of U 235 is completely destroyed in an atom bomb, then approximate total energy released is (given that the energy released per fission is 200 MeV )

Question

If 5 mg of U 235 is completely destroyed in an atom bomb, then approximate total energy released is (given that the energy released per fission is 200 MeV ), 4 × 10 8 J, 6 × 10 9 J, 5 × 10 7 J, 3 × 10 10 J

MARKS App · Accepted Answer

Number of uranium atom is, N = N A 235 × 5 × 10 - 3 ⇒ N = 6 . 022 × 10 23 235 × 5 × 10 - 3 = 1 . 28 × 10 19 To energy in this fission is, E = N × 200 MeV ⇒ E = 1 . 28 × 10 19 × 200 × 10 6 × 1 . 6 × 10 - 19 J ⇒ E ≈ 4 × 10 8 J

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