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If $5 x^2+\lambda y^2=20$ represents a rectangular hyperbola, then $\lambda$ equals
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$-5$
Since the general equation of second degree represents a rectangular hyperbola, if $\Delta \neq 0, h^2 \gt a b$ and coefficient of $x^2+$ coefficient of $y^2=0$. Therefore the given equation represents a rectangular hyperbola, if $\lambda+5=0$ i.e., $\lambda=-5$.
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