Search any question & find its solution
Question:
Answered & Verified by Expert
If $50 \%$ of the reactant is converted into a product in a first order reaction in $25 \mathrm{~min}$, how much of it would react in $100 \mathrm{~min}$ ?
Options:
Solution:
1373 Upvotes
Verified Answer
The correct answer is:
$93.75 \%$
Number of half-lives $=\frac{100}{25}=4$, i.e., $n=4$
Amount of the substance left after 4 half-lives
$\begin{aligned}
&=\frac{A^{0}}{2^{n}} \\
&=\frac{A^{0}}{2^{4}}=\frac{A^{0}}{16}=\frac{100}{16}=6.25 \%
\end{aligned}$
$(\because n=4)$
$\therefore$ Amount of the substance converted into the product in $100 \mathrm{~min}=100-6.25=93.75 \%$
Amount of the substance left after 4 half-lives
$\begin{aligned}
&=\frac{A^{0}}{2^{n}} \\
&=\frac{A^{0}}{2^{4}}=\frac{A^{0}}{16}=\frac{100}{16}=6.25 \%
\end{aligned}$
$(\because n=4)$
$\therefore$ Amount of the substance converted into the product in $100 \mathrm{~min}=100-6.25=93.75 \%$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.