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If $65 \mathrm{~kJ}$ of work is done on the system and it releases and it releases $25 \mathrm{~kJ}$ of heat. What is change in internal energy of the system?
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$40 \mathrm{~kJ}$
$\begin{aligned} & \Delta E=\delta Q+\delta W \\ & =-25+65 \\ & =40 \mathrm{KJ}\end{aligned}$
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