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If $A=\left[\begin{array}{ccc}0 & 2 & 0 \\ 0 & 0 & 3 \\ -2 & 2 & 0\end{array}\right] \text {and } B=\left[\begin{array}{ccc}1 & 2 & 3 \\ 3 & 4 & 5 \\ 5 & -4 & 0\end{array}\right]$, then the element of $3^{\text {rd }}$ row and third column in $A B$ will be
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The correct answer is:
$4$
In the product $A B$, the required element
$C_{33}=(-2) 3+2.5+0.0=-6+10=4$
$C_{33}=(-2) 3+2.5+0.0=-6+10=4$
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