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If $a>0$ discriminant of $a x^2+2 b x+c$ is -ve, then
$\left|\begin{array}{ccc}a & b & a x+b \\ b & c & b x+c \\ a x+b & b x+c & 0\end{array}\right|$ is
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$\left|\begin{array}{ccc}a & b & a x+b \\ b & c & b x+c \\ a x+b & b x+c & 0\end{array}\right|$ is
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2314 Upvotes
Verified Answer
The correct answer is:
-ve
-ve
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