Search any question & find its solution
Question:
Answered & Verified by Expert
If $\mathrm{A}=\left[\begin{array}{ccc}1 & 0 & -2 \\ 2 & -3 & 4\end{array}\right]$, then the matrix $\mathrm{X}$ for which $2 \mathrm{X}+3 \mathrm{~A}=$ 0 holds true is
Options:
Solution:
2106 Upvotes
Verified Answer
The correct answer is:
$\left[\begin{array}{ccc}-\frac{3}{2} & 0 & 3 \\ -3 & \frac{9}{2} & -6\end{array}\right]$
$\because 2 X+3 A=0$
$\Rightarrow x=\frac{-3}{2} A$
$\Rightarrow x=\frac{-3}{2}\left[\begin{array}{ccc}1 & 0 & -2 \\ 2 & -3 & 4\end{array}\right]$
$\Rightarrow X=\left[\begin{array}{ccc}-\frac{3}{2} & 0 & 3 \\ -3 & \frac{9}{2} & -6\end{array}\right]$
$\Rightarrow x=\frac{-3}{2} A$
$\Rightarrow x=\frac{-3}{2}\left[\begin{array}{ccc}1 & 0 & -2 \\ 2 & -3 & 4\end{array}\right]$
$\Rightarrow X=\left[\begin{array}{ccc}-\frac{3}{2} & 0 & 3 \\ -3 & \frac{9}{2} & -6\end{array}\right]$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.