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If $A=\{1,2,3,4,5,6\}$, then the number of subsets of A which contain at least two elements is
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57
Given set $A=\{1,2,3,4,5,6\}$
Number of subsets of $A$ which contain at least two elements is ${ }^{6} C_{2}+{ }^{6} C_{3}+{ }^{6} C_{4}+{ }^{6} C_{5}+{ }^{6} C_{6}$
$=2^{6}-{ }^{6} C_{0}-{ }^{6} C_{1}=64-1-6=57$
Number of subsets of $A$ which contain at least two elements is ${ }^{6} C_{2}+{ }^{6} C_{3}+{ }^{6} C_{4}+{ }^{6} C_{5}+{ }^{6} C_{6}$
$=2^{6}-{ }^{6} C_{0}-{ }^{6} C_{1}=64-1-6=57$
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