If a 1 and 2 Sinh − 1 ( 1 − a 2 a ) = lo g ( 1 − x 1 + x ) , then x =, 2 a, 3 a, 4 a, a

If a 1 and 2 Sinh − 1 ( 1 − a 2 a ) = lo g ( 1 − x 1 + x ) , then x =

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If $\mathrm{a} < 1$ and $2 \operatorname{Sinh}^{-1}\left(\frac{a}{\sqrt{1-a^2}}\right)=\log \left(\frac{1+x}{1-x}\right)$, then $x=$

MathematicsInverse Trigonometric FunctionsAP EAMCETAP EAMCET 2017 (25 Apr Shift 1)

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Solution:

1791 Upvotes Verified Answer

The correct answer is: $a$

No solution. Refer to answer key.

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