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Question: Answered & Verified by Expert
If a<1 and b<1, then the sum of the series aa+b+a2a2+b2+a3a3+b3+ is
MathematicsSequences and SeriesJEE Main
Options:
  • A a1-a+ab1-ab
  • B a21-a2+ab1-ab
  • C b1-b+a1-a
  • D b21-b2+ab1-ab
Solution:
2733 Upvotes Verified Answer
The correct answer is: a21-a2+ab1-ab
We have, a<1, b<1

   ab=ab<1

Now, aa+b+a2a2+b2+a3a3+b3+

 =   a2+a4+a6++ab+ab2+ab3+

= a21-a2+ab1-ab

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