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If $(a,-2 a), a>0$ is the midpoint of a line segment intercepted between the co-ordinate axes, then the equation of the line is
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$2 x-y=4 a$
(A)
Given point $(a,-2 a)$ is the midpoint of the intercepts.
Let Points $A, B, M$ be as shown in figure.
Hence the intercept points are $(2 \mathrm{a}, 0)$ and $(0,-4 \mathrm{a})$
Equation of line from intercept in intercept form.
$\frac{x}{2 a}+\frac{y}{-4 a}=1 \Rightarrow 2 x-y=4 a$
Given point $(a,-2 a)$ is the midpoint of the intercepts.
Let Points $A, B, M$ be as shown in figure.
Hence the intercept points are $(2 \mathrm{a}, 0)$ and $(0,-4 \mathrm{a})$
Equation of line from intercept in intercept form.
$\frac{x}{2 a}+\frac{y}{-4 a}=1 \Rightarrow 2 x-y=4 a$
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