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If $A=3 \hat{i}+4 \hat{j}$ and $B=7 \hat{i}+24 \hat{j}$, the vector having the same magnitude as $B$ and parallel to $A$ is
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The correct answer is:
$15 \hat{i}+20 \hat{j}$
$|B|=\sqrt{7^2+(24)^2}=\sqrt{625}=25$
Unit vector in the direction of $A$ will be
$\hat{A}=\frac{3 \hat{i}+4 \hat{j}}{5}$
So required vector $=25\left(\frac{3 \hat{i}+4 \hat{j}}{5}\right)=15 \hat{i}+20 \hat{j}$
Unit vector in the direction of $A$ will be
$\hat{A}=\frac{3 \hat{i}+4 \hat{j}}{5}$
So required vector $=25\left(\frac{3 \hat{i}+4 \hat{j}}{5}\right)=15 \hat{i}+20 \hat{j}$
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