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If $\overrightarrow{\mathrm{A}}=a_{1} \hat{\imath}+a_{2} \hat{\jmath}$ and $\overrightarrow{\mathrm{B}}=b_{1} \hat{\imath}+b_{2} \hat{\jmath}$ are perpendicular to each other then
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The correct answer is:
$\frac{a_{1}}{b_{2}}=-\frac{\mathrm{a}_{2}}{\mathrm{~b}_{1}}$
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