Search any question & find its solution
Question:
Answered & Verified by Expert
If $A=\left[a_{i j}\right]_{3 \times 3}=\left[\begin{array}{lll}3 & 2 & 4 \\ 1 & 4 & 1 \\ 2 & 6 & 3\end{array}\right]$ and $A_{i j}$ is a cofactor of $a_{i j}$, then the value of $a_{21} A_{21}+a_{22} A_{22}+a_{23} A_{23}$ is equal to
Options:
Solution:
1385 Upvotes
Verified Answer
The correct answer is:
8
$a_{21} A_{21}, a_{22} A_{22}+a_{23} A_{23}=|A|=3 \times(12-6)-2(3-2)+4(6-8)=8$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.