Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If a and b are arbitrary constants, then the order and degree of the differential equation of the family of curves ax2+by2=2 respectively are
MathematicsDifferential EquationsJEE Main
Options:
  • A 2,2
  • B 1,2
  • C 1,1
  • D 2,1
Solution:
2082 Upvotes Verified Answer
The correct answer is: 2,1
ax2+by2=1

On differentiating w.r.t. x

ax+bydydx=0 ... 1

Again differentiating w.r.t. x

a+byd2ydx2+bdydx2=0 ... 2

From 1 & 2, we get, 

x-byd2ydx2-bdydx2+bydydx=0

-xyd2ydx2-xdydx2+ydydx=0

Hence, order =2, degree =1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.