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If $A$ and $B$ are square matrices of the same order, then
(i) $(\mathrm{AB})^{\prime}=$
(ii) $(\mathrm{kA})^{\prime}=$ . (k is any scalar)
(iii) $[\mathrm{k}(\mathrm{A}-\mathrm{B})]^{\prime}=$
(i) $(\mathrm{AB})^{\prime}=$
(ii) $(\mathrm{kA})^{\prime}=$ . (k is any scalar)
(iii) $[\mathrm{k}(\mathrm{A}-\mathrm{B})]^{\prime}=$
Solution:
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Verified Answer
(i) $\mathrm{B}^{\prime} \mathrm{A}^{\prime}$ (ii) $\mathrm{kA} \mathrm{A}^{\prime}$ (iii) $\mathrm{k}\left(\mathrm{A}^{\prime}-\mathrm{B}^{\prime}\right)$
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