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If $A$ and $B$ are two events of a random experiment such that $P(\bar{A})=\frac{2}{3}, P(B)=\frac{4}{15}$ and $\mathrm{P}(\mathrm{A} \cap \bar{B})=\frac{1}{5}$, then
$$
\sqrt{195[P(B \mid(A \cup \bar{B}))+P(A \cup B)]}=
$$
Options:
$$
\sqrt{195[P(B \mid(A \cup \bar{B}))+P(A \cup B)]}=
$$
Solution:
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Verified Answer
The correct answer is:
11
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