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If $\mathrm{A}$ and $\mathrm{B}$ are two events such that
$$
\mathrm{P}(\mathrm{A} \mid \mathrm{B})=\mathrm{p}, \mathrm{P}(\mathrm{A})=\mathrm{p}, \mathrm{P}(\mathrm{B})=\frac{1}{3}
$$
and $\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{5}{9}$, then $\mathrm{p}=$
$$
\mathrm{P}(\mathrm{A} \mid \mathrm{B})=\mathrm{p}, \mathrm{P}(\mathrm{A})=\mathrm{p}, \mathrm{P}(\mathrm{B})=\frac{1}{3}
$$
and $\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{5}{9}$, then $\mathrm{p}=$
Solution:
1076 Upvotes
Verified Answer
$\frac{1}{3}$
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