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If A and B simultaneously toss one coin each every time, each 50 times, then the probability of not getting tail on both the coins is
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The correct answer is:
$\left(\frac{3}{4}\right)^{50}$
$S=\{(T, T),(H, H),(T, H),(H, T)\}$.
Probability of not getting tail $=\frac{3}{4}$
$\therefore$ The required probability $=\left(\frac{3}{4}\right)^{50}$
Probability of not getting tail $=\frac{3}{4}$
$\therefore$ The required probability $=\left(\frac{3}{4}\right)^{50}$
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