If a , b and c are distinct positive real numbers such that Δ 1 = a b c b c a c a b and Δ 2 = b c - a 2 a c - b 2 a b - c 2 a c - b 2 a b - c 2 b c - a 2 a b - c 2 b c - a 2 a c - b 2 , then

Question

If a , b and c are distinct positive real numbers such that Δ 1 = a b c b c a c a b and Δ 2 = b c - a 2 a c - b 2 a b - c 2 a c - b 2 a b - c 2 b c - a 2 a b - c 2 b c - a 2 a c - b 2 , then, Δ 1 = Δ 2, Δ 1 2 + Δ 2 = 0, Δ 1 2 = Δ 2, Δ 1 2 = Δ 2 2

MARKS App · Accepted Answer

Elements of Δ 2 are co-factors of the elements of Δ 1 Hence Δ 1 2 = Δ 2

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