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If $\bar{a}, \bar{b}$ and $\bar{c}$ are vectors such that $|\bar{a}|=\left|\frac{\bar{b}}{2}\right|=\left|\frac{\bar{c}}{3}\right|=1 ; \bar{b}$ and $\bar{c}$ are perpendicular; and the projections of $\bar{b}$ and $\bar{c}$ on $\bar{a}$ are equal then $|\bar{a}-\bar{b}+\bar{c}|=$
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The correct answer is:
$\sqrt{14}$
No solution. Refer to answer key.
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