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If $a, b$ are natural numbers such that $2013+a^{2}=b^{2}$, then the minimum possible value of $a b$ is
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Verified Answer
The correct answer is:
$658$
$(b-a)(b+a)=2013=3 \times 11 \times 61$
$ab$ minimum when $b-a=33$
$\begin{array}{l}
b+a=61 \\
a=14
\end{array}$
$a b=14 \times 47=658$
$ab$ minimum when $b-a=33$
$\begin{array}{l}
b+a=61 \\
a=14
\end{array}$
$a b=14 \times 47=658$
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