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If $a, b$ are positive real numbers such that the lines ax $+9 y=5$ and $4 x+b y=3$ are parallel, then the least possible value of $a+b$ is
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The correct answer is:
12
$\frac{a}{4}=\frac{9}{b} \Rightarrow a b=36$
using $A M \geq G \cdot M$
$\frac{a+b}{2} \geq \sqrt{a b} \Rightarrow a+b \geq 12$
using $A M \geq G \cdot M$
$\frac{a+b}{2} \geq \sqrt{a b} \Rightarrow a+b \geq 12$
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